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本文将系统梳理开发者最常用的十大算法,并为每项算法配合生活/工业案例和Python代码示例进行说明。

def quick_sort(arr):if len(arr) <= 1:return arrpivot = arr[len(arr) // 2]# 选择中间作为基准left = [x for x in arr if x < pivot]middle = [x for x in arr if x == pivot]right = [x for x in arr if x > pivot]return quick_sort(left) + middle + quick_sort(right)# 示例:[3, 6, 8, 10, 1, 2, 1] -> [1, 1, 2, 3, 6, 8, 10]
def binary_search(arr, target):low, high = 0, len(arr) - 1while low <= high:mid = (low + high) // 2if arr[mid] == target: return midelif arr[mid] < target: low = mid + 1else: high = mid - 1return -1
def is_palindrome(s):left, right = 0, len(s) - 1while left < right:if s[left] != s[right]: return Falseleft += 1right -= 1return True
def max_sum_subarray(arr, k):n = len(arr)if n < k: return 0window_sum = sum(arr[:k])max_val = window_sumfor i in range(n - k):window_sum = window_sum - arr[i] + arr[i + k] # 滑动:减去左边,加上右边max_val = max(max_val, window_sum)return max_val
from collections import dequedef bfs(graph, start):visited = set([start])queue = deque([start])while queue:node = queue.popleft()print(node, end=" ")for neighbor in graph[node]:if neighbor not in visited:visited.add(neighbor)queue.append(neighbor)# graph = {'A': ['B', 'C'], 'B': ['D'], ...}
def dfs(graph, node, visited=None):if visited is None: visited = set()visited.add(node)print(node, end=" ")for neighbor in graph[node]:if neighbor not in visited:dfs(graph, neighbor, visited)
import heapqdef dijkstra(graph, start):pq = [(0, start)] # (距离, 节点)distances = {node: float('inf') for node in graph}distances[start] = 0while pq:curr_dist, curr_node = heapq.heappop(pq)if curr_dist > distances[curr_node]: continuefor neighbor, weight in graph[curr_node].items():dist = curr_dist + weightif dist < distances[neighbor]:distances[neighbor] = distheapq.heappush(pq, (dist, neighbor))return distances
def climb_stairs(n):if n <= 2: return ndp = [0] * (n + 1)dp[1], dp[2] = 1, 2for i in range(3, n + 1):dp[i] = dp[i-1] + dp[i-2] # 状态转移return dp[n]
def coin_change_greedy(coins, amount):coins.sort(reverse=True) # 面值大的在前count = 0for coin in coins:count += amount // coinamount %= coinreturn count if amount == 0 else -1
def backtrack(path, choices):if not choices: # 满足条件print(path)returnfor i in range(len(choices)):# 做选择path.append(choices[i])# 递归backtrack(path, choices[:i] + choices[i+1:])# 撤销选择(这就是回溯的核心)path.pop()
学习算法时,不要死记代码,要记**“场景触发词”**: